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-.001x^2+3x-1800=360
We move all terms to the left:
-.001x^2+3x-1800-(360)=0
We add all the numbers together, and all the variables
-0.001x^2+3x-2160=0
a = -0.001; b = 3; c = -2160;
Δ = b2-4ac
Δ = 32-4·(-0.001)·(-2160)
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{0.36}}{2*-0.001}=\frac{-3-\sqrt{0.36}}{-0.002} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{0.36}}{2*-0.001}=\frac{-3+\sqrt{0.36}}{-0.002} $
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